15x^2=x+2=

Solution for 15x^2=x+2= equation:

15x^2=x+2=

We move all terms to the left:

15x^2-(x+2)=0

We get rid of parentheses

15x^2-x-2=0

We add all the numbers together, and all the variables

15x^2-1x-2=0

a = 15; b = -1; c = -2;
Δ = b2-4ac
Δ = -12-4·15·(-2)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-11}{2*15}=\frac{-10}{30}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+11}{2*15}=\frac{12}{30}
=2/5
$